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06:14 PM	alchemia:	helle 1 am chemist
01:30 PM	emma1991:	can anybody name me a reagent which can change a ketone to a secondary alchol
01:29 PM	emma1991:	can anybody name me a reagent which can change a ketone to a secondary alchol
01:29 PM	emma1991:	can anybody name me a reagent which can change a ketone to a secondary alshol
01:28 PM	emma1991:	does any body here so A level chemistry or has done it recently??
01:28 PM	emma1991:	does any body here so A level chemistry or has done it recently??
01:28 PM	emma1991:	does any body here so A level chemistry or has done it recently??
01:27 PM	emma1991:	does any body here so A level chemistry or has done it recently??
01:27 PM	emma1991:	does any body here so A level chemistry or has done it recently??
01:27 PM	emma1991:
08:41 PM	texasguy:	hello
08:41 PM	texasguy:	hello
09:21 PM	Spitze:	http://www.chatzy.com/365581508899 <--- A better chat room if you're still looking for help
08:57 PM	alison:	because the electrons are not accessible
08:56 PM	alison:	means it has more directionality, aka electrons stick out farther. this is why less p character means a weaker base
08:44 PM	angel2:	hey what does "more p character mean" again
08:42 PM	Anne Edelstein:	oh, right, thanks
08:42 PM	Das ist lächerlich:	When you get an alkyl shift in carbocation rearrangement and it makes a bigger/smaller ring
08:41 PM	Anne Edelstein:	what do you mean by that??? like R/S stuff on rings??
08:40 PM	Das ist lächerlich:	I'd bet**
08:40 PM	Das ist lächerlich:	I think no ring rearrangements might have just been on that first test. I'd be that they're fair game now...
08:39 PM	Das ist lächerlich:	http://www.chatzy.com/365581508899 <---- More stable chat room that doesn't flash every 2 seconds
08:39 PM	shell21:	wishful thinking.
08:39 PM	shell21:	I thought she mentioned that she woujldn't give us something like that/....
08:39 PM	shell21:	aw3esome.
08:38 PM	angel2:	i think so
08:38 PM	shell21:	are we responsible for ring rearrangements?
08:37 PM	Das ist lächerlich:	Yeah... It's like an Sn2
08:36 PM	angel2:	hmm
08:36 PM	Anne Edelstein:	oh schnikes that confuses me too
08:36 PM	angel2:	?
08:36 PM	angel2:	because apparently it's an sn2
08:36 PM	angel2:	but it doesnt
08:36 PM	Anne Edelstein:	shouldnt it attack at the more substituated carbon??
08:35 PM	Das ist lächerlich:	http://www.chatzy.com/365581508899
08:35 PM	Das ist lächerlich:	Hey you guys... This chat room sucks because it keeps kicking people out... Go to this link and I think we can use a better one:
08:35 PM	angel2:	sorry och3 base
08:35 PM	angel2:	where did that base attack?
08:35 PM	angel2:	with the epoxide and the base naoch3?
08:35 PM	angel2:	yesterday
08:35 PM	angel2:	hey do you guys remember that last question we did
08:34 PM	prarthana1:	so did we solve the ether problem someone just asked?
08:34 PM	prarthana1:	oh okcool
08:34 PM	prarthana1:	oh ok
08:34 PM	angel2:	yeah
08:34 PM	angel2:	we dont
08:34 PM	Anne Edelstein:	yea dr. nerz said we dont have to do that one
08:34 PM	Das ist lächerlich:	Yeah... I'm not sure if we have to know how to do that one... I think AIBN makes radicals, though
08:33 PM	Anne Edelstein:	wait, let me just check really quickly
08:33 PM	Anne Edelstein:	we dont have to know how to do that one i dont think
08:32 PM	prarthana1:	3rd down on the left
08:32 PM	Das ist lächerlich:	I keep getting kicked out of this chat room... Anyone want to try a different one? http://www.chatzy.com/365581508899
08:32 PM	prarthana1:	page 4 of the rxn flashcards
08:31 PM	Das ist lächerlich:	Pg 4 of what? Which column and problem?
08:31 PM	Anne Edelstein:	are the jeopardy answers online, elle?
08:31 PM	prarthana1:	yesi am looking at page 4
08:30 PM	prarthana1:	yes
08:30 PM	Das ist lächerlich:	Prar: Are you looking at a specific problem?
08:30 PM	elle:	on page 2 of jeopardy, in the reductions column, 300, is that no rxn?
08:29 PM	lightfoot:	it becomes an R-Cl group
08:29 PM	elle:	it would attack the H from the HI, then it has too many bonds and is postively charged
08:29 PM	prarthana:	butane, that is.
08:28 PM	prarthana:	ok, but then how does the butane react with that? there is no + or - part on that molecule
08:28 PM	Anne Edelstein:	making SO2 gas and a chloride ion
08:28 PM	Das ist lächerlich:	You could protonate it or something
08:28 PM	Das ist lächerlich:	To break an ether you'd have to turn it into a good leaving grou
08:28 PM	Anne Edelstein:	bc you have a negative charge on the oxygen with a single bond, it folds in and creates another double bonded o and kicks the cl off
08:27 PM	angelo:	only if it's in an aq. solution
08:27 PM	angelo:	only if it's in an aq. solution
08:27 PM	Anne Edelstein:	yea, thats the one where you have the leaving group as o=s-o (-)and a cl attached to the s also
08:27 PM	hellolo:	How does one break an ether (on flashcards page 6)?
08:27 PM	lightfoot:	it's butane and not butanol?
08:26 PM	lightfoot:	on the flashcards she doesn't put the aldehydes?
08:26 PM	prarthana:	does anyone understand the flashcard rxn with the butane and So2Cl2?
08:25 PM	lightfoot:	on primary alcohols are we suppose to assume the acid is the major?
08:25 PM	Anne Edelstein:	Hey guys, question, if you have two compounds and they are diasteriomeric in relation to eachother but one compd is a meso group do they lose any rela
08:23 PM	Das spitze:	Could be an aldehyde, or it could've been the second one and you'd have a carboxylic acid
08:23 PM	Das spitze:	So you'll get some sort of carbonyl--not necessarily a ketone
08:23 PM	Das spitze:	Yeah, then a base could come take a beta-H and you're set
08:21 PM	lightfoot:	and then you get a ketone?
08:20 PM	Das spitze:	Does that make sense?
08:19 PM	angel:	will deprotonate it?
08:19 PM	angel:	?
08:18 PM	angel:	which oh
08:18 PM	Spitze:	Then you have to get rid of the extra H that's stuck on there, then you've got your good leaving group
08:18 PM	Spitze:	Then the alcohol that you have will attack the Cr, just like we did in those other ones, and it'll make the chromium ester
08:18 PM	Spitze:	So, the H2Cr04 is an acid, so one of it's -OHs will deprotonate because it's in an aqueous solution
08:17 PM	Spitze:	If you've got a specific problem, let me try to look at it... My gut is that it'll make a Chromium ester thing
08:16 PM	Spitze:	Like, mechanistically?
08:15 PM	Hello?:	how the hell does the h2cro4 reactgion work?how bout this
08:14 PM	Hello?:	alright well how bout this
08:14 PM	Spitze:	Since we're all in here, I'll just say that I'm willing to answer any questions that I can
08:11 PM	Spitze:	I don't even really know if she's coming
08:10 PM	Spitze:	Not yet
08:10 PM	Hello?:	is she there?
08:07 PM	Spitze:	The star!
08:02 PM	Student:	Dr. Nerz?
09:10 PM	Hi Dr Nerz:	I have a question about oxidizing agents
09:04 PM	your welcome:	your welcome
08:55 PM	David F:	oh ok, thanks Dr. Nerz
08:54 PM	nerz:	it is described in the tables - the salmon tables
08:54 PM	nerz:	there is a peak in the finger print region that indicates the compound is a trans alkene. There is another peak that shows it is a monosubstituted al
08:52 PM	nerz:	termination steps are not desirable - the product can form from it
08:52 PM	David F:	the lab just confused me a little
08:52 PM	David F:	oh ok, that's what i thought
08:51 PM	nerz:	the last step in a propagation is the formation of the product and the original radical
08:51 PM	David F:	what should we have been looking for?
08:51 PM	nerz:	so in a free radical reaction there are propagation steps which are teh real reaction
08:50 PM	David F:	i thought I saw a trans peak on both
08:50 PM	David F:	i had trouble distinguishing between the trans and 1-nonene compound on the IR on the last test
08:50 PM	David F:	well my last question was about IR's
08:49 PM	David F:	hm, ok...
08:49 PM	nerz:	termination is just the combination of two radicals - any two radicals
08:48 PM	David F:	so what was wanted for the termination step?
08:48 PM	nerz:	you should have a stable molecule and a free rad - the original free rad
08:46 PM	nerz:	that is the end of a free radical reaction
08:44 PM	David F:	i ended with the dichlorobutane and chlorine radical. where does it go from there?
08:43 PM	David F:	i didn't know that we needed to include that step, and i'm not entirely sure what it is
08:43 PM	David F:	ok thanks! my second question was about the termination step for the chlorine radical reaction for lab
08:42 PM	nerz:	yes
08:42 PM	David F:	and an aprotic will only stabilize the cation?
08:41 PM	nerz:	yes, the leaving group anion needs stabilization too
08:41 PM	nerz:	sn1/e1 the leaving group leaves and normally makes an anion and cation. The stabilization of both accelerates the reaction
08:41 PM	David F:	oh, you mean the leaving group anion?
08:40 PM	David F:	but i thought the fact that they don't solvate anions would be an acelerating factor, like an sn2/e2?
08:40 PM	nerz:	they will not solvate anions well so they are not the best for sn1
08:36 PM	David F:	and do polar aprotic have any effect on sn1/e1?
08:36 PM	nerz:	yes, they do for that reason
08:35 PM	nerz:	what did your email say. I just got home from my office
08:34 PM	David F:	my first was: do polar protic solvents decelerate sn2/e2 because they surround the anion?
08:33 PM	David F:	i just had a few questions
08:32 PM	nerz:	what did your email say. I just got home from my office
08:32 PM	David F:	I realize that you may not have had time based on your email, so I thought I'd come here
08:31 PM	David F:	Hi Dr. Nerz, did you get my email by any chance?
08:22 PM	nerz:	i am here
08:20 PM	David F:	Dr. Nerz?